Week 10: Whose Race Is It?#
One outcome set, two interests
The turn#
Week 9 gave us distributions: where each strategy finished across repeated, shared scenarios.
A distribution does not prefer a strategy.
This week asks:
When the same joint race outcomes serve two cars, what changes when we rank them for the team rather than one named driver?
We change the rule for ranking. We do not change the evidence.
Objective and stakeholder#
An objective is the explicit rule used to rank candidate decisions.
A stakeholder is the named interest that rule represents.
Our two objectives use the same points scale:
- team: maximise expected constructors’ points across car 14 and car 22
- car 14: maximise car 14’s expected race points
The quantity and stakeholder belong in the same sentence. Maximise points
does not say enough.
Joint plan and expected points#
A joint plan is one candidate strategy containing outcomes for two distinct cars under every supplied path.
Expected points is a probability-weighted mean:
for each path:
score the finish or finishes named by the objective
multiply that score by the path weight
add the weighted scoresIt is a ranking over possible outcomes, not a promise about the result of one race.
The real rule, and where it stops#
For one ordinary race whose leader completes at least 75% of scheduled distance:
| Finish | P1 | P2 | P3 | P4 | P5 |
|---|---|---|---|---|---|
| Points | 25 | 18 | 15 | 12 | 10 |
| Finish | P6 | P7 | P8 | P9 | P10 |
|---|---|---|---|---|---|
| Points | 8 | 6 | 4 | 2 | 1 |
FIA 2026 Section A, Issue 03, Articles A2.1.4(b) and A2.2.1: constructors’ points use both cars’ results. Expected points is our synthetic decision model, not an FIA method or recommendation.
Validate before ranking#
For every plan/path pair, require:
- exactly one record for car 14 and one for car 22
- each finish inside P1–P10
- distinct finishing positions for the two cars
Across paths, require:
- each path has one non-negative weight
- the weights sum to
1.00 - every plan has outcomes on the same path set
Invalid input produces no ranking. A plausible winner from malformed evidence is still malformed.
Four failures to stop at the door#
| Input | Failure |
|---|---|
weights 0.25, 0.25, 0.25 | probability mass is 0.75 |
| car 14 appears twice | car 22 is missing |
| car 22 finishes P11 | finish is outside the lookup |
| car 14 P3, car 22 P3 | two cars occupy one position |
One more check protects comparability: a plan missing Path 4 cannot be ranked against plans that include it.
Stop. Report the invalid record. Do not calculate around it.
The synthetic fixture (1 of 2)#
Each cell is car 14 / car 22. Every path has weight 0.25.
| Joint plan | Path 1 | Path 2 |
|---|---|---|
| protect 14 | P1 / P8 | P2 / P7 |
| balance | P2 / P3 | P3 / P4 |
| split risk | P1 / P8 | P2 / P7 |
These are supplied counterfactual outcomes, not predictions from the FIA and not measured Formula 1 data.
The synthetic fixture (2 of 2)#
Same plans, same car order, same 0.25 path weights.
| Joint plan | Path 3 | Path 4 |
|---|---|---|
| protect 14 | P3 / P6 | P5 / P4 |
| balance | P4 / P5 | P6 / P2 |
| split risk | P7 / P2 | P8 / P1 |
All three plans now have four complete joint outcomes. We have not chosen an objective yet, so we have not chosen a winner.
Derive balance path by path (1 of 2)#
Under the team objective, score both cars and add them.
| Path | Joint finish | Points | Team total | Weighted |
|---|---|---|---|---|
| 1 | P2 / P3 | 18 + 15 | 33 | 8.25 |
| 2 | P3 / P4 | 15 + 12 | 27 | 6.75 |
The path total comes before the weighting. Adding only car 14 would answer the driver question while labelling it as the team question.
Derive balance path by path (2 of 2)#
| Path | Joint finish | Points | Team total | Weighted |
|---|---|---|---|---|
| 3 | P4 / P5 | 12 + 10 | 22 | 5.50 |
| 4 | P6 / P2 | 8 + 18 | 26 | 6.50 |
E[team points | balance]
= 0.25(33) + 0.25(27) + 0.25(22) + 0.25(26)
= 27.00Every figure above is synthetic. The arithmetic is still checkable.
Rank for the team#
Apply the same both-car calculation to all three plans.
| Joint plan | Team totals by path | Expected team points |
|---|---|---|
| protect 14 | 29, 24, 23, 22 | 24.50 |
| balance | 33, 27, 22, 26 | 27.00 |
| split risk | 29, 24, 24, 29 | 26.50 |
Team selection: balance. It ranks first under the declared objective:
maximise expected constructors’ points across both cars.
Expected does not mean certain. Another supplied path could still favour another plan.
Change stakeholder, not evidence#
Now maximise car 14’s expected points.
Keep fixed:
- the three joint plans
- all four paths and their
0.25weights - both cars’ finishes on every path
- the P1–P10 points lookup
Change one operation: score only car 14’s finish before weighting.
No resimulation. No new draw. The stakeholder changes; the evidence does not.
Rank for car 14#
| Joint plan | Car 14 points by path | Expected car 14 points |
|---|---|---|
| protect 14 | 25, 18, 15, 10 | 17.00 |
| balance | 18, 15, 12, 8 | 13.25 |
| split risk | 25, 18, 6, 4 | 13.25 |
Car-14 selection: protect 14. The two alternatives tie below it at
13.25.
The fixture did not change. The ranking changed because the named interest did.
Account for the trade#
Compare the team selection, balance, with the car-14 selection, protect 14.
| Interest measured | Balance | Protect 14 | Change |
|---|---|---|---|
| team | 27.00 | 24.50 | -2.50 |
| car 14 | 13.25 | 17.00 | +3.75 |
| car 22 | 13.75 | 7.50 | -6.25 |
The objective change benefits car 14 and costs car 22 enough that the team’s expected total also falls. That is an account of named interests, not a claim that one objective is neutral, selfish or correct.
Four outputs, four questions#
| Output | Question answered |
|---|---|
| expected team points | Which plan ranks highest for both cars’ points? |
| expected driver points | Which plan ranks highest for one named car? |
| finish distribution | Where might one strategy finish? |
| head-to-head probability | How often does one option beat another? |
A plan can win more often and still lose on expected points when the losses cost more than the wins gain. Week 11 must keep the objective ranking distinct from the probability and from each distribution.
Two assertions protect the meaning#
Catch a one-car team total:
assert team_points(path) == points(car14) + points(car22)Catch changed evidence between objectives:
before = fingerprint(plans, paths, weights, outcomes)
rank_for_team()
rank_for_car14()
assert fingerprint(plans, paths, weights, outcomes) == beforeThe first protects the stakeholder. The second proves the new ranking came from a new objective rather than a new race.
What leaves this week#
The objective-change report records:
- FIA 2026 Section A, Issue 03 and the at-least-75% race assumption
- the synthetic boundary and candidate set
- both objectives, with each stakeholder named
- both complete rankings and selected plans
- team, car-14 and car-22 deltas
- limitations of the supplied paths
Week 11 consumes the expected constructors’-points ranking as given. Its wall may also show a distribution or head-to-head probability, but it must name the objective because those quantities do not replace it.